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A363753 a(n) = Sum_{k=0..n} (-1)^k*F(k-1)*F(k)*F(k+1)/2, where F(n) is the Fibonacci number A000045(n). 4
0, 0, 1, -2, 13, -47, 213, -879, 3762, -15873, 67342, -285098, 1207966, -5116586, 21674919, -91815276, 388937619, -1647563169, 6979194475, -29564334305, 125236542640, -530510487155, 2247278519916, -9519624520452, 40325776676748, -170822731106052, 723616701297373 (list; graph; refs; listen; history; text; internal format)
OFFSET
0,4
COMMENTS
Alternating sum of the product of three consecutive Fibonacci numbers, divided by two.
Can also be seen as the alternating sum of the Fibonomial coefficients (n+1,3), A001655.
This sequence is part of a suite of sums over triple products of Fibonacci numbers. Subba Rao (1953) gives closed-form expressions for several Fibonacci sums of this type.
LINKS
K. Subba Rao, Some properties of Fibonacci numbers, The American Mathematical Monthly, 60(10):680-684, December 1953.
FORMULA
a(n) = ((-1)^n*(F(n+1)^3 - F(n)^3) + F(n+2) - 2)/8.
a(n) = ((-1)^n*F(3*n+1) + 4*F(n+2) - 5)/20.
a(n) = -2*a(n-1) + 9*a(n-2) - 3*a(n-3) - 4*a(n-4) + a(n-5).
a(-n) = A215037(n-3).
G.f.: x^2/((1 - x)*(1 + 4*x - x^2)*(1 - x - x^2)).
20*a(n) = (-1)^n*A033887(n) + 4*A000045(n+2) - 5. - R. J. Mathar, Jun 27 2023
MATHEMATICA
LinearRecurrence[{-2, 9, -3, -4, 1}, {0, 0, 1, -2, 13}, 27]
CROSSREFS
Other sequences with the product of three Fibonacci numbers as a summand (the sequence may have a shifted [and scaled] version of the summand given here).
A005968: F(k)^3, A119284: (-1)^k*F(k)^3, A215037: F(k-1)*F(k)*F(k+1),
A363753: (-1)^k*F(k-1)*F(k)*F(k+1), A163198: F(2k)^3, A163200: F(2k+1)^3,
A256178: F(2k)*F(2k+1)*F(2k+2), this sequence: (-1)^k*F(k-1)*F(k)*F(k+1),
A363754: F(2k-1)*F(2k)*F(2k+1).
Sequence in context: A176060 A168172 A127305 * A333519 A270294 A330539
KEYWORD
sign,easy
AUTHOR
Hans J. H. Tuenter, Jun 19 2023
STATUS
approved

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Last modified May 9 15:13 EDT 2024. Contains 372352 sequences. (Running on oeis4.)