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A365858
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Number of cyclic compositions of 2*n-1 into odd parts.
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3
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1, 2, 3, 5, 10, 19, 41, 94, 211, 493, 1170, 2787, 6713, 16274, 39651, 97109, 238838, 589527, 1459961, 3626242, 9030451, 22542397, 56393862, 141358275, 354975433, 892893262, 2249412291, 5674891017, 14335757586, 36259245523, 91815545801, 232745229290, 590586152235, 1500020153485, 3813274653414
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OFFSET
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1,2
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COMMENTS
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Also the number of cyclic compositions into an odd number of odd parts; because such a sum must be odd, alternating terms are zero and have been removed.
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LINKS
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FORMULA
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G.f.: (1/2) * Sum_{k odd} (phi(k)/k)*log((1+x^k-x^(2k))/(1-x^k-x^(2*k))), where phi(n) = A000010(n).
a(n) = (1/(2*n-1)) * Sum_{k divides 2n-1} phi(k)*A000204((2*n-1)/k).
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MATHEMATICA
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Table[1/(2*n - 1) * Sum[EulerPhi[k]*LucasL[(2*n - 1)/k], {k, Divisors[2*n - 1]}], {n, 1, 40}] (* Vaclav Kotesovec, Sep 22 2023 *)
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PROG
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(PARI)
N=99; x='x+O('x^N); B(x)=x/(1-x^2);
A=Vec(sum(k=1, N, eulerphi(k)/k*log(1/(1-B(x^k)))));
(Python)
from sympy import totient, lucas, divisors
def A365858(n): return sum(totient(((n<<1)-1)//k)*(lucas(k)-((k&1^1)<<1)) for k in divisors((n<<1)-1, generator=True))//((n<<1)-1) # Chai Wah Wu, Sep 23 2023
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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