A358753 a(n) = 1 if bigomega(n) == 3 (mod 4), otherwise 0.

0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 1, 0, 0, 0, 0, 0, 1, 0, 1, 0, 0, 0, 0, 0, 0, 1, 1, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 1, 1, 0, 0, 0, 0, 1, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 1, 0, 1, 0, 1, 0, 0, 0, 0, 1, 1, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 1, 1, 0, 0, 1, 0, 0, 1, 0, 0, 0, 0, 1, 0, 0, 0, 1, 0, 1, 1, 0, 0, 0, 0, 0, 0, 1, 1, 0, 0, 1

Offset

1

Comments

Equally, a(n) = 1 if A349905(n) == 3 (mod 4), otherwise 0.

Links

Antti Karttunen, Table of n, a(n) for n = 1..100000

Index entries for characteristic functions

Index entries for sequences computed from exponents in factorization of n

Formula

a(n) = [A349905(n) == 3 (mod 4)], where [ ] is the Iverson bracket.

a(n) = A066829(n) - A358751(n).

a(n) = A358773(A003961(n)).

For all n >= 1, a(n) >= A101605(n).

Prog

(PARI) A358753(n) = (3==(bigomega(n)%4));

Crossrefs

Characteristic function of A358763.

Cf. A001222, A003415, A003961, A010051, A010873, A066829, A349905, A358751, A358773.

Differs from A101605 for the first time at n=128, where a(128) = 1, while A101605(128) = 0.

Sequence in context: A025460 A169673 A101605 * A175854 A353678 A135133

Adjacent sequences: A358750 A358751 A358752 * A358754 A358755 A358756

Keyword

nonn

Author

Antti Karttunen, Nov 29 2022

Status

approved