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A258028
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Numbers k such that D(prime(k), 3) > 0, where D( * , 3) = 3rd difference.
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5
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1, 3, 5, 8, 10, 14, 15, 17, 20, 23, 26, 29, 31, 33, 35, 36, 38, 39, 41, 43, 45, 46, 50, 52, 55, 57, 60, 61, 65, 67, 71, 73, 76, 78, 79, 81, 83, 86, 90, 93, 96, 98, 100, 102, 105, 107, 109, 110, 113, 114, 117, 118, 120, 124, 126, 129, 131, 134, 136, 138, 140
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OFFSET
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1,2
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COMMENTS
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LINKS
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FORMULA
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D(prime(k), 3) = P(k+3) - 3*P(k+2) + 3*P(k+1) - P(k), where P(m) = prime(m) for m >= 1.
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EXAMPLE
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D(prime(1), 3) = 7 - 3*5 + 3*3 - 2 < 0, so a(1) = 1;
D(prime(2), 3) = 11 - 3*7 + 3*5 - 3 > 0;
D(prime(3), 3) = 13 - 3*11 + 3*7 - 5 < 0, so a(3) = 3;
D(prime(4), 3) = 17 - 3*13 + 3*11 - 7 > 0.
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MATHEMATICA
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d = Differences[Table[Prime[n], {n, 1, 400}], 3];
u1 = Flatten[Position[d, 0]] (* A064149 *)
u2 = Flatten[Position[Sign[d], 1]] (* A258027 *)
u3 = Flatten[Position[Sign[d], -1]] (* A258028 *)
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CROSSREFS
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KEYWORD
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nonn,easy
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AUTHOR
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STATUS
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approved
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