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A231014
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Number of months after which it is not possible to have the same calendar for the entire month with the same number of days, in the Julian calendar.
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24
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1, 2, 4, 5, 7, 10, 11, 12, 13, 16, 19, 21, 24, 25, 27, 28, 30, 33, 36, 39, 41, 42, 44, 45, 47, 48, 49, 50, 51, 53, 56, 58, 59, 61, 62, 65, 66, 67, 70, 71, 73, 74, 76, 79, 82, 83, 84, 85, 87, 88, 90, 91, 93, 96, 97, 99, 100, 102, 104, 105, 107, 108, 111, 113, 116, 119, 120
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OFFSET
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1,2
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COMMENTS
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In the Julian calendar, a year is a leap year if and only if it is a multiple of 4 and all century years are leap years.
Assuming this fact, this sequence is periodic with a period of 336.
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LINKS
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PROG
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(PARI) m=[0, 3, 3, 6, 1, 4, 6, 2, 5, 0, 3, 5]; n=[31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31]; y=vector(336, i, (m[((i-1)%12)+1]+((5*((i-1)\48)+(((i-1)\12)%4)-!((i-1)%48)-!((i-2)%48))))%7); x=vector(336, i, n[((i-1)%12)+1]+!((i-2)%48)); for(p=0, 336, j=0; for(q=0, 336, if(y[(q%336)+1]==y[((q+p)%336)+1]&&x[(q%336)+1]==x[((q+p)%336)+1], j=1; break)); if(j==0, print1(p", ")))
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CROSSREFS
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KEYWORD
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nonn,easy
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AUTHOR
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STATUS
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approved
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