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A217448
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Least k > 0 such that 1 + n^2 and 1 + (n+k)^2 have the same smallest prime factor.
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1
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2, 6, 2, 26, 2, 74, 2, 4, 2, 404, 2, 6, 2, 366, 2, 514, 2, 4, 2, 1564, 2, 6, 2, 1106, 2, 4010, 2, 4, 2, 34, 2, 6, 2, 10, 2, 2594, 2, 4, 2, 22334, 2, 6, 2, 16, 2, 58, 2, 4, 2, 64, 2, 6, 2, 29062, 2, 18710, 2, 4, 2, 10, 2, 6, 2, 42, 2, 17428, 2, 4, 2, 16, 2, 6
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OFFSET
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1,1
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COMMENTS
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A089120(n): smallest prime factor of n^2 + 1.
Conjecture: a(n) exists for all n.
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LINKS
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EXAMPLE
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a(10) = 404 because 10^2 + 1 = 101, (10+404)^2+1 = 101*1697 so A089120(10) = A089120(414) = 101;
a(170) = 404274 because 170^2 + 1 = 28901, (170+404274)^2+1 = 163574949137 = 28901* 5659837 so A089120(170) = A089120(40444) = 28901.
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MAPLE
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with(numtheory):T:=array(1..100): for n from 1 to 100 do:x:=factorset(n^2+1):n1:=nops(x): T[n] := x[1]:od:for a from 1 to 80 do:p:=T[a]:ii:=0:for k from 1 to 50000 while(ii=0) do: z:=factorset((a+k)^2+1): n2:=nops(z):if z[1]=p then printf(`%d, `, k):ii:=1:else fi:od:od:
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MATHEMATICA
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sspf[n_]:=Module[{c=FactorInteger[1+n^2][[1, 1]], k=1}, While[ FactorInteger[ 1+ (n+k)^2][[1, 1]]!=c, k++]; k]; Array[sspf, 80] (* Harvey P. Dale, Oct 12 2012 *)
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PROG
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(PARI)
A020639(n) = if(1==n, n, factor(n)[1, 1]);
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CROSSREFS
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KEYWORD
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AUTHOR
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STATUS
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approved
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