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A166986
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a(n) = 2*floor((n+2)/log(2)) - 4.
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3
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4, 6, 10, 12, 16, 18, 20, 24, 26, 30, 32, 36, 38, 42, 44, 46, 50, 52, 56, 58, 62, 64, 68, 70, 72, 76, 78, 82, 84, 88, 90, 94, 96, 98, 102, 104, 108, 110, 114, 116, 120, 122, 124, 128, 130, 134, 136, 140, 142, 146, 148, 150, 154, 156, 160, 162, 166, 168, 172, 174, 176
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OFFSET
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1,1
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COMMENTS
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With a different offset, partial sums of A022934, cf. formula.
The first terms appear to satisfy a linear recurrence relation of order 10 (or higher if more terms are included), but this can be proved to be impossible, cf. R. Israel's post to the SeqFan list. - M. F. Hasler, Apr 11 2019
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LINKS
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FORMULA
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a(n) = 2*floor((n+2)/log(2)) - 4.
a(n) = 2*Sum_{k=2,..,n+1} A022934(k).
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MAPLE
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seq(2*floor((n+2)/log(2))-4, n=1..100); # Robert Israel, Apr 11 2019
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MATHEMATICA
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PROG
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(PARI) vector( 80, n, 2*floor((n+2)/log(2)) - 4) \\ Michel Marcus, Jul 06 2015
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CROSSREFS
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KEYWORD
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easy,nonn
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AUTHOR
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STATUS
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approved
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