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A120247
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Triangle of Hankel transforms of binomial(n+k, k).
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3
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1, 1, -1, 1, -3, -1, 1, -6, -10, 1, 1, -10, -50, 35, 1, 1, -15, -175, 490, 126, -1, 1, -21, -490, 4116, 5292, -462, -1, 1, -28, -1176, 24696, 116424, -60984, -1716, 1, 1, -36, -2520, 116424, 1646568, -3737448, -736164, 6435, 1, 1, -45, -4950, 457380, 16818516, -133613766, -131589315, 9202050, 24310, -1
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OFFSET
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0,5
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COMMENTS
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Row k is the Hankel transform of C(n+k, k).
The matrix inverse starts
1;
1, -1;
-2, 3, -1;
-15, 24, -10, 1;
434, -700, 300, -35, 1;
47670, -76950, 33075, -3920, 126, -1;
-19787592, 31943835, -13733720, 1629936, -52920, 462, -1; - R. J. Mathar, Mar 22 2013
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LINKS
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FORMULA
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T(n, k) = (cos(pi*k/2) - sin(pi*k/2))*( Product{j=0..k-1} C(n+j+1, k+1)/Product{j=0..k-1} C(k+j+1, k+1) ).
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EXAMPLE
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Triangle begins
1;
1, -1;
1, -3, -1;
1, -6, -10, 1;
1, -10, -50, 35, 1;
1, -15, -175, 490, 126, -1;
1, -21, -490, 4116, 5292, -462, -1;
1, -28, -1176, 24696, 116424, -60984, -1716, 1;
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MAPLE
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(cos(Pi*k/2)-sin(Pi*k/2))*mul(binomial(n+j+1, k+1), j=0..k-1)/mul(binomial(k+j+1, k+1), j=0..k-1) ;
simplify(%) ;
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MATHEMATICA
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p[m_, k_]:= Product[Binomial[m+j, k+1], {j, k}];
T[n_, k_]:= (-1)^Floor[(k+1)/2]*p[n, k]/p[k, k];
Table[T[n, k], {n, 0, 12}, {k, 0, n}]//Flatten (* G. C. Greubel, Mar 15 2023 *)
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PROG
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(Magma)
p:= func< m, k | k eq 0 select 1 else (&*[Binomial(m+j, k+1): j in [1..k]]) >;
A120247:= func< n, k | (-1)^Floor((k+1)/2)*p(n, k)/p(k, k) >;
(SageMath)
def p(m, k): return product(binomial(m+j+1, k+1) for j in range(k))
def A120247(n, k): return (-1)^((k+1)//2)*p(n, k)/p(k, k)
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CROSSREFS
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KEYWORD
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AUTHOR
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STATUS
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approved
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