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A008970
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Triangle T(n,k) = P(n,k)/2, n >= 2, 1 <= k < n, of one-half of number of permutations of 1..n such that the differences have k runs with the same signs.
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13
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1, 1, 2, 1, 6, 5, 1, 14, 29, 16, 1, 30, 118, 150, 61, 1, 62, 418, 926, 841, 272, 1, 126, 1383, 4788, 7311, 5166, 1385, 1, 254, 4407, 22548, 51663, 59982, 34649, 7936, 1, 510, 13736, 100530, 325446, 553410, 517496, 252750, 50521, 1, 1022, 42236, 433162, 1910706, 4474002, 6031076, 4717222, 1995181, 353792
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OFFSET
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2,3
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REFERENCES
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L. Comtet, Advanced Combinatorics, Reidel, 1974, p. 261, #13, P_{n,k}.
F. N. David, M. G. Kendall and D. E. Barton, Symmetric Function and Allied Tables, Cambridge, 1966, p. 260, Table 7.2.1.
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LINKS
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FORMULA
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Let P(n, k) = number of permutations of [1..n] with k "sequences". Note that A008970 gives P(n, k)/2. Then g.f.: Sum_{n, k} P(n, k) *u^k * t^n/n! = (1 + u)^(-1) * ((1 - u) * (1 - sin(v + t * cos(v))-1) where u = sin(v).
P(n, 1) = 2, P(n, k) = k*P(n-1, k) + 2*P(n-1, k-1) + (n-k)*P(n-1, k-2).
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EXAMPLE
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Triangle starts
1;
1, 2;
1, 6, 5;
1, 14, 29, 16;
1, 30, 118, 150, 61;
...
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MAPLE
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T:= proc(n, k) option remember; `if`(n<2, 0, `if`(k=1, 1,
k*T(n-1, k) + 2*T(n-1, k-1) + (n-k)*T(n-1, k-2)))
end:
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MATHEMATICA
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p[n_ /; n >= 2, 1] = 2; p[n_ /; n >= 2, k_] /; 1 <= k <= n := p[n, k] = k*p[n-1, k] + 2*p[n-1, k-1] + (n-k)*p[n-1, k-2]; p[n_, k_] = 0; t[n_, k_] := p[n, k]/2; A008970 = Flatten[ Table[ t[n, k], {n, 2, 11}, {k, 1, n-1}]] (* Jean-François Alcover, Apr 03 2012, after given recurrence *)
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CROSSREFS
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A008303 gives circular version of P(n, k).
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KEYWORD
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AUTHOR
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EXTENSIONS
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More terms from Larry Reeves (larryr(AT)acm.org), Feb 01 2001
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STATUS
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approved
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