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A367117 Place n points in general position on each side of an equilateral triangle, and join every pair of the 3*n+3 boundary points by a chord; sequence gives number of vertices in the resulting planar graph. 8
3, 12, 72, 282, 795, 1818, 3612, 6492, 10827, 17040, 25608, 37062, 51987, 71022, 94860, 124248, 159987, 202932, 253992, 314130, 384363, 465762, 559452, 666612, 788475, 926328, 1081512, 1255422, 1449507, 1665270, 1904268, 2168112, 2458467, 2777052, 3125640, 3506058, 3920187, 4369962 (list; graph; refs; listen; history; text; internal format)
OFFSET
0,1
COMMENTS
"In general position" implies that the internal lines (or chords) only have simple intersections. There is no interior point where three or more chords meet.
Note that although the number of k-gons in the graph will vary as the edge points change position, the total number of regions will stay constant as long as all internal vertices remain simple.
LINKS
Scott R. Shannon, Image for n = 1.
Scott R. Shannon, Image for n = 2.
Scott R. Shannon, Image for n = 5.
FORMULA
Theorem: a(n) = (3/4)*(n+1)*(3*n^3+n^2+4).
a(n) = A367119(n) - A367118(n) + 1 by Euler's formula.
MATHEMATICA
A367117[n_]:=3/4(n+1)(3n^3+n^2+4); Array[A367117, 50, 0] (* Paolo Xausa, Nov 09 2023 *)
CROSSREFS
Cf. A367118 (regions), A367119 (edges).
If the boundary points are equally spaced, we get A274585, A092866, A274586, A092867. - N. J. A. Sloane, Nov 09 2023
Sequence in context: A103366 A335643 A277457 * A228386 A175836 A293138
KEYWORD
nonn
AUTHOR
STATUS
approved

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Last modified May 15 09:20 EDT 2024. Contains 372540 sequences. (Running on oeis4.)