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A327420
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Building sums recursively with the divisibility properties of their partial sums.
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5
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1, 0, 2, 3, 6, 5, 9, 7, 15, 4, 14, 11, 21, 13, 16, 8, 35, 17, 26, 19, 30, 12, 28, 23, 46, 18, 38, 10, 49, 29, 45, 31, 77, 20, 50, 27, 63, 37, 52, 24, 68, 41, 54, 43, 74, 25, 64, 47, 96, 34, 62, 32, 95, 53, 70, 42, 94, 36, 86, 59, 91, 61, 88, 33, 166, 51, 85
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OFFSET
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0,3
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COMMENTS
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Let R(n) = [k : n + 1 >= k >= 2] and divsign(s, k) = 0 if k does not divide s, else k if s/k is even and else -k. Compute s(k) = s(k+1) + divsign(s(k+1), k) with initial value s(n+2) = n + 1, k running down from n + 1 to 2. Then a(n) = s(2) if n > 0 and a(0) = s(n+2) = 0 + 1 = 1 as R(0) is empty in this case.
Examples: If n = 8 then R(8) = [9, 8, ..., 2] and the partial sums s are [0, 8, 8, 8, 8, 12, 15, 15] giving a(8) = 15. If p is prime, then the partial sums are [0, p, p, ..., p] since p is the only integer in R(p) diving p, i. e. the primes are the fixed points of this sequence. In the example section the computation of a(9) is traced.
Apparently the sequence is a permutation of the nonnegative integers.
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LINKS
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FORMULA
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EXAMPLE
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The computation of a(9) = 4:
[ k: s(k) = s(k+1) + divsign(s(k+1),k)]
[10: 0, 10, -10]
[ 9: 9, 0, 9]
[ 8: 9, 9, 0]
[ 7: 9, 9, 0]
[ 6: 9, 9, 0]
[ 5: 9, 9, 0]
[ 4: 9, 9, 0]
[ 3: 6, 9, -3]
[ 2: 4, 6, -2]
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MAPLE
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divsign := (s, k) -> `if`(irem(s, k) <> 0, 0, (-1)^iquo(s, k)*k):
A327420 := proc(n) local s, k; s := n + 1;
for k from s by -1 to 2 do
s := s + divsign(s, k) od;
return s end:
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PROG
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(SageMath)
s = n + 1
r = srange(s, 1, -1)
for k in r:
if k.divides(s):
s += (-1)^(s//k)*k
return s
print([A327420(n) for n in (0..66)])
(Julia)
divsign(s, k) = rem(s, k) == 0 ? (-1)^div(s, k)*k : 0
s = n + 1
for k in n+1:-1:2 s += divsign(s, k) end
s
end
[A327420(n) for n in 0:66] |> println
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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