|
|
A326714
|
|
a(n) = binomial(n,2) + (2-adic valuation of n).
|
|
1
|
|
|
0, 2, 3, 8, 10, 16, 21, 31, 36, 46, 55, 68, 78, 92, 105, 124, 136, 154, 171, 192, 210, 232, 253, 279, 300, 326, 351, 380, 406, 436, 465, 501, 528, 562, 595, 632, 666, 704, 741, 783, 820, 862, 903, 948, 990, 1036, 1081, 1132, 1176, 1226, 1275, 1328, 1378
(list;
graph;
refs;
listen;
history;
text;
internal format)
|
|
|
OFFSET
|
1,2
|
|
COMMENTS
|
2^a(n) is the smallest integer m >= n such that binomial(m,n) is divisible by 2^binomial(n,2).
2^a(n) is conjectured to be the order of the smallest n-symmetric graph.
|
|
LINKS
|
|
|
FORMULA
|
|
|
EXAMPLE
|
Binomial(4,2) is 6. In addition, the 2-adic value of 4 is 2, so a(4) = 8.
|
|
MATHEMATICA
|
a[n_] := Binomial[n, 2] + IntegerExponent[n, 2]; Array[a, 60] (* Giovanni Resta, Dec 03 2019 *)
|
|
PROG
|
(Python)
for i in range(1, 70):
j = i
res = i*(i-1)//2
while j%2 == 0:
res = res + 1
j = j // 2
print(str(res), end = ', ')
(Python)
|
|
CROSSREFS
|
|
|
KEYWORD
|
nonn
|
|
AUTHOR
|
|
|
STATUS
|
approved
|
|
|
|