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A297283
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Numbers whose base-14 digits have equal down-variation and up-variation; see Comments.
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4
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1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 15, 30, 45, 60, 75, 90, 105, 120, 135, 150, 165, 180, 195, 197, 211, 225, 239, 253, 267, 281, 295, 309, 323, 337, 351, 365, 379, 394, 408, 422, 436, 450, 464, 478, 492, 506, 520, 534, 548, 562, 576, 591, 605, 619
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OFFSET
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1,2
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COMMENTS
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Suppose that n has base-b digits b(m), b(m-1), ..., b(0). The base-b down-variation of n is the sum DV(n,b) of all d(i)-d(i-1) for which d(i) > d(i-1); the base-b up-variation of n is the sum UV(n,b) of all d(k-1)-d(k) for which d(k) < d(k-1). The total base-b variation of n is the sum TV(n,b) = DV(n,b) + UV(n,b). See the guide at A297330.
Differs first from A029959 after the zero for 2759 = 1011_14, which is not a palindrome in base 14 but has UV(2759,14) = DV(2759,14) = 1. - R. J. Mathar, Jan 23 2018
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LINKS
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EXAMPLE
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619 in base-14: 3,2,3 having DV = 1, UV = 1, so that 619 is in the sequence.
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MATHEMATICA
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g[n_, b_] := Map[Total, GatherBy[Differences[IntegerDigits[n, b]], Sign]];
x[n_, b_] := Select[g[n, b], # < 0 &]; y[n_, b_] := Select[g[n, b], # > 0 &];
b = 14; z = 2000; p = Table[x[n, b], {n, 1, z}]; q = Table[y[n, b], {n, 1, z}];
w = Sign[Flatten[p /. {} -> {0}] + Flatten[q /. {} -> {0}]];
Take[Flatten[Position[w, -1]], 120] (* A297282 *)
Take[Flatten[Position[w, 0]], 120] (* A297283 *)
Take[Flatten[Position[w, 1]], 120] (* A297284 *)
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CROSSREFS
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KEYWORD
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nonn,base,easy
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AUTHOR
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STATUS
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approved
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