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A294864
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Solution of the complementary equation a(n) = a(n-2) + b(n-2) + n, where a(0) = 1, a(1) = 2, b(0) = 3, and (a(n)) and (b(n)) are increasing complementary sequences.
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3
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1, 2, 6, 9, 15, 21, 29, 38, 48, 59, 71, 84, 99, 114, 131, 148, 167, 187, 208, 230, 253, 277, 302, 328, 356, 384, 414, 444, 476, 508, 542, 576, 613, 649, 688, 726, 767, 807, 850, 892, 937, 982, 1029, 1076, 1125, 1174, 1225, 1276, 1329, 1382, 1437, 1493, 1550
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OFFSET
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0,2
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COMMENTS
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The increasing complementary sequences a() and b() are uniquely determined by the titular equation and initial values. See A294860 for a guide to related sequences.
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LINKS
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EXAMPLE
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a(0) = 1, a(1) = 2, b(0) = 3
b(1) = 4 (least "new number")
a(2) = a(0) + b(0) + 2 = 6
Complement: (b(n)) = (3, 4, 5, 7, 8, 10, 11, 12, 13, 14, 16, ...)
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MATHEMATICA
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mex := First[Complement[Range[1, Max[#1] + 1], #1]] &;
a[0] = 1; a[1] = 2; b[0] = 3;
a[n_] := a[n] = a[n - 2] + b[n - 2] + n;
b[n_] := b[n] = mex[Flatten[Table[Join[{a[n]}, {a[i], b[i]}], {i, 0, n - 1}]]];
Table[a[n], {n, 0, 18}] (* A294864 *)
Table[b[n], {n, 0, 10}]
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CROSSREFS
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KEYWORD
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nonn,easy
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AUTHOR
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STATUS
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approved
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