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A283895
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Relative of Hofstadter Q-sequence: a(1) = 41, a(2) = 2; thereafter a(n) = a(n-a(n-1)) + a(n-a(n-2)).
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5
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41, 2, 41, 2, 41, 2, 41, 2, 41, 2, 41, 2, 41, 2, 41, 2, 41, 2, 41, 2, 41, 2, 41, 2, 41, 2, 41, 2, 41, 2, 41, 2, 41, 2, 41, 2, 41, 2, 41, 2, 41, 43, 2, 84, 2, 84, 2, 84, 2, 84, 2, 84, 2, 84, 2, 84, 2, 84, 2, 84, 2, 84, 2, 84, 2, 84, 2, 84, 2, 84, 2, 84, 2, 84, 2
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OFFSET
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1,1
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COMMENTS
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In calculating terms of this sequence, use the convention that a(n)=0 for n<=0.
Most terms in this sequence alternate between 2 and a large constant. Such runs of terms are eventually separated by either 224 or 562 other terms, and each run is approximately twice as long as the previous.
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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