|
|
A273932
|
|
Integers m such that ceiling(sqrt(m!)) is prime.
|
|
0
|
|
|
|
OFFSET
|
1,1
|
|
COMMENTS
|
This sequence includes the known solutions of Brocard's problem as of 2016 (see A146968).
|
|
LINKS
|
|
|
EXAMPLE
|
3 is in the sequence because 3! = 6, sqrt(6) = 2.449489742783178..., the ceiling of which is 3, which is prime.
4 is in the sequence because 4! = 24, sqrt(24) = 4.898979485566356..., the ceiling of which is 5, which is prime.
|
|
MATHEMATICA
|
Select[Range[3200]], PrimeQ[Ceiling[Sqrt[#!]]] &]
|
|
PROG
|
(Python)
from math import isqrt, factorial
from itertools import count, islice
from sympy import isprime
def A273932_gen(): # generator of terms
return filter(lambda n:isprime(1+isqrt(factorial(n)-1)), count(1))
|
|
CROSSREFS
|
|
|
KEYWORD
|
nonn,more
|
|
AUTHOR
|
|
|
EXTENSIONS
|
|
|
STATUS
|
approved
|
|
|
|