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A271346
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Numbers k such that the final digit of k^k is 6.
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2
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4, 6, 8, 12, 14, 16, 24, 26, 28, 32, 34, 36, 44, 46, 48, 52, 54, 56, 64, 66, 68, 72, 74, 76, 84, 86, 88, 92, 94, 96, 104, 106, 108, 112, 114, 116, 124, 126, 128, 132, 134, 136, 144, 146, 148, 152, 154, 156, 164, 166, 168, 172, 174, 176, 184, 186, 188, 192, 194
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OFFSET
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1,1
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COMMENTS
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The values of n^n (A000312) end in every digit except for 2 and 8. The sequence of final digits of n^n (A056849) is periodic with period 20; for n=1,2,... the last digits are [1, 4, 7, 6, 5, 6, 3, 6, 9, 0, 1, 6, 3, 6, 5, 6, 7, 4, 9, 0]. Thus, 6 is the most common final digit of n^n. Since 6 does not occur at any odd index in the list above, all terms of a(n) are even. Also, from the distribution of 6's in the list, we can see that the difference between any two consecutive values of a(n) will be 2, 4 or 8.
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LINKS
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FORMULA
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G.f.: 2*x*(1 + x^2)*(2 + x - x^2 + x^3 + 2*x^4) / ((1 - x)^2*(1 + x)*(1 - x + x^2)*(1 + x + x^2)). - Colin Barker, Dec 13 2018
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MAPLE
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MATHEMATICA
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LinearRecurrence[{1, 0, 0, 0, 0, 1, -1}, {4, 6, 8, 12, 14, 16, 24}, 59] (* Ray Chandler, Mar 08 2017 *)
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PROG
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(Magma) I:=[4, 6, 8, 12, 14, 16, 24]; [n le 7 select I[n] else Self(n-1)+Self(n-6)-Self(n-7): n in [1..60]]; // Vincenzo Librandi, Oct 09 2017
(PARI) Vec(2*x*(1 + x^2)*(2 + x - x^2 + x^3 + 2*x^4) / ((1 - x)^2*(1 + x)*(1 - x + x^2)*(1 + x + x^2)) + O(x^59)) \\ Colin Barker, Dec 13 2018
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CROSSREFS
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KEYWORD
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nonn,base,easy
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AUTHOR
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STATUS
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approved
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