|
|
A190823
|
|
Number of permutations of 2 copies of 1..n introduced in order 1..n with no element equal to another within a distance of 2.
|
|
6
|
|
|
1, 0, 0, 1, 10, 99, 1146, 15422, 237135, 4106680, 79154927, 1681383864, 39034539488, 983466451011, 26728184505750, 779476074425297, 24281301468714902, 804688068731837874, 28269541494090294129, 1049450257149017422000, 41050171013933837206545
(list;
graph;
refs;
listen;
history;
text;
internal format)
|
|
|
OFFSET
|
0,5
|
|
COMMENTS
|
Also the number of 2-uniform set partitions of {1..2n} such that no block has its two vertices differing by less than 3. For example, the a(4) = 10 set partitions are:
{{1,4}, {2,6}, {3,7}, {5,8}}
{{1,4}, {2,7}, {3,6}, {5,8}}
{{1,5}, {2,6}, {3,7}, {4,8}}
{{1,5}, {2,6}, {3,8}, {4,7}}
{{1,5}, {2,7}, {3,6}, {4,8}}
{{1,5}, {2,8}, {3,6}, {4,7}}
{{1,6}, {2,5}, {3,7}, {4,8}}
{{1,6}, {2,5}, {3,8}, {4,7}}
{{1,7}, {2,5}, {3,6}, {4,8}}
{{1,8}, {2,5}, {3,6}, {4,7}}
(End)
|
|
LINKS
|
|
|
FORMULA
|
a(n) = 2*(n+1)*a(n-1) - 2*(3*n-5)*a(n-2) + 2*(3*n-8)*a(n-3) - 2*(n-4)*a(n-4) - a(n-5) (proved). - Everett Sullivan, Mar 16 2017
a(n) ~ 2^(n+1/2) * n^n / exp(n+2), based on Sullivan's formula. - Vaclav Kotesovec, Mar 21 2017
|
|
EXAMPLE
|
All solutions for n=4 (read downwards):
1 1 1 1 1 1 1 1 1 1
2 2 2 2 2 2 2 2 2 2
3 3 3 3 3 3 3 3 3 3
4 4 4 4 1 4 4 1 4 4
1 1 2 1 4 2 1 4 2 2
3 3 1 2 2 3 2 3 1 3
2 4 4 4 3 4 3 2 3 1
4 2 3 3 4 1 4 4 4 4
|
|
MATHEMATICA
|
a[0]=1; a[1]=0; a[2]=0; a[3]=1; a[4]=10; a[5]=99; a[n_] := a[n] = (2*n+2) a[n-1] - (6*n-10) a[n-2] + (6*n-16) a[n-3] - (2*n-8) a[n-4] - a[n-5]; Array[a, 20, 0] (* based on Sullivan's formula, Giovanni Resta, Mar 20 2017 *)
dtui[{}]:={{}}; dtui[set:{i_, ___}]:=Join@@Function[s, Prepend[#, s]&/@dtui[Complement[set, s]]]/@Table[{i, j}, {j, Select[set, #>i+2&]}];
Table[Length[dtui[Range[n]]], {n, 0, 12, 2}] (* Gus Wiseman, Feb 27 2019 *)
|
|
PROG
|
(Magma) I:=[1, 0, 0, 1, 10, 99]; [n le 5 select I[n] else 2*n*Self(n-1) -2*(3*n-8)*Self(n-2) +2*(3*n-11)*Self(n-3) -2*(n-5)*Self(n-4) -Self(n-5): n in [1..40]]; // G. C. Greubel, Dec 03 2023
(SageMath)
@CachedFunction
if (n<6): return (1, 0, 0, 1, 10, 99)[n]
else: return 2*(n+1)*a(n-1) - 2*(3*n-5)*a(n-2) + 2*(3*n-8)*a(n-3) - 2*(n-4)*a(n-4) - a(n-5)
|
|
CROSSREFS
|
Distance of 1 instead of 2 gives |A000806|.
|
|
KEYWORD
|
nonn,easy
|
|
AUTHOR
|
|
|
EXTENSIONS
|
|
|
STATUS
|
approved
|
|
|
|