|
|
A173111
|
|
Triangle read by rows, A173108 * the diagonalized variant of A173110
|
|
3
|
|
|
1, 1, 2, 1, 5, 1, 15, 2, 3, 52, 5, 3, 203, 15, 6, 6, 877, 52, 15, 6, 4140, 203, 45, 12, 20, 21147, 877, 156, 30, 20, 115975, 4140, 609, 90, 40, 60, 678570, 21147, 2631, 312, 100, 60
(list;
table;
graph;
refs;
listen;
history;
text;
internal format)
|
|
|
OFFSET
|
0,3
|
|
COMMENTS
|
Row sums = A173110: (1, 1, 3, 6, 20, 60, 230, 950, 4420, 22230,...).
|
|
LINKS
|
|
|
FORMULA
|
Let triangle A173108 = Q, and M = an infinite lower triangular matrix with A173110 as the rightmost diagonal and the rest zeros. Triangle A173111 = Q*M.
|
|
EXAMPLE
|
First few rows of the triangle =
1;
1;
2, 1;
5, 1;
15, 2, 3;
52, 5, 3;
203, 15, 6, 6;
877, 52, 15, 6;
4140, 203, 45, 12, 20;
21147, 877, 156, 30, 20;
115975, 4140, 609, 90, 40, 60;
678570, 21147, 2631, 312, 100, 60;
...
Example: row 7 = termwise products of (877, 52, 5, 1) and (1, 1, 3, 6) =
(877, 52, 15, 6); where (877, 52, 5, 1) = row 7 of triangle A173108, and
(1, 1, 3, 6) = the first four terms of sequence A173109.
|
|
CROSSREFS
|
|
|
KEYWORD
|
|
|
AUTHOR
|
|
|
STATUS
|
approved
|
|
|
|