|
|
A147520
|
|
a(n) = Smallest number x such that Euler Polynomial x^2 + x + 41 is divisible by 41^n.
|
|
3
|
|
|
0, 40, 1721, 139563, 14268368, 1636255182, 6386359423, 1953929098233, 149759650255065, 1814531956108700, 243422399538851918, 9662500171353620019, 122479951673184550424, 12148820281768361731597, 177497315692809432279207, 14173382150616650630276616, 1225594969529024683212496795
(list;
graph;
refs;
listen;
history;
text;
internal format)
|
|
|
OFFSET
|
1,2
|
|
COMMENTS
|
For values of x^2 + x + 41, see A147521. For values (x^2 + x + 41)/(41^n), see A147522.
By Hensel's lemma, x^2 + x + 41 has two roots mod 41^n; their sum == -1 mod 41^n. Thus 0 <= a(n) < 41^n/2. - Robert Israel, Apr 09 2018
|
|
LINKS
|
|
|
MAPLE
|
f:= n -> min(map(t -> rhs(op(t)), [msolve(x^2+x+41, 41^n)])):
|
|
MATHEMATICA
|
a = {}; Do[x = 0; While[Mod[x^2 + x + 41, 41^n] != 0, x++ ]; AppendTo[a, x]; Print[{n, x, x^2 + x + 41, (x^2 + x + 41)/41^n}], {n, 1, 6}]; a (* Artur Jasinski *)
|
|
CROSSREFS
|
|
|
KEYWORD
|
nonn
|
|
AUTHOR
|
|
|
EXTENSIONS
|
|
|
STATUS
|
approved
|
|
|
|