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A110310
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Expansion of (1-x+x^2)/((x^2+x+1)*(x^2+5*x+1)).
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5
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1, -7, 36, -173, 827, -3960, 18973, -90907, 435564, -2086913, 9998999, -47908080, 229541401, -1099798927, 5269453236, -25247467253, 120967883027, -579591947880, 2776991856373, -13305367333987, 63749844813564, -305443856733833, 1463469438855599, -7011903337544160
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OFFSET
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0,2
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LINKS
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FORMULA
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a(n+2) = - 5*a(n+1) - a(n) - (-1)^n*A109265(n+3).
a(n) = -6*a(n-1) - 7*a(n-2) - 6*a(n-3) - a(n-4) for n>3. - Colin Barker, Apr 30 2019
a(n) = (1/2)*(3*ChevyshevU(n, -5/2) - ChebyshevU(n, -1/2)). - G. C. Greubel, Jan 02 2023
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MAPLE
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seriestolist(series((1-x+x^2)/((x^2+x+1)*(x^2+5*x+1)), x=0, 25));
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MATHEMATICA
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LinearRecurrence[{-6, -7, -6, -1}, {1, -7, 36, -173}, 40] (* G. C. Greubel, Jan 02 2023 *)
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PROG
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(PARI) Vec((1-x+x^2)/((1+x+x^2)*(1+5*x+x^2)) + O(x^25)) \\ Colin Barker, Apr 30 2019
(Magma) R<x>:=PowerSeriesRing(Integers(), 40); Coefficients(R!( (1-x+x^2)/((1+x+x^2)*(1+5*x+x^2)) )); // G. C. Greubel, Jan 02 2023
(SageMath)
def U(n, x): return chebyshev_U(n, x)
def A110310(n): return (1/2)*(3*U(n, -5/2) - U(n, -1/2))
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CROSSREFS
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KEYWORD
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easy,sign
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AUTHOR
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STATUS
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approved
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