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A093879 First differences of A004001. 16
0, 1, 0, 1, 1, 0, 0, 1, 1, 1, 0, 1, 0, 0, 0, 1, 1, 1, 1, 0, 1, 1, 0, 1, 0, 0, 1, 0, 0, 0, 0, 1, 1, 1, 1, 1, 0, 1, 1, 1, 0, 1, 1, 0, 1, 0, 0, 1, 1, 0, 1, 0, 0, 1, 0, 0, 0, 1, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 0, 1, 1, 1, 1, 0, 1, 1, 1, 0, 1, 1, 0, 1, 0, 0, 1, 1, 1, 0, 1, 1, 0, 1, 0, 0, 1, 1, 0, 1, 0, 0, 1, 0, 0, 0 (list; graph; refs; listen; history; text; internal format)
OFFSET
1,1
COMMENTS
All the terms are 0 or 1: it is easy to show that if {b(n)} = A004001, b(n)>=b(n-1) and b(n)<n, therefore the first differences form an infinite binary word. - Benoit Cloitre, Jun 05 2004
LINKS
J. Grytczuk, Another variation on Conway's recursive sequence, Discr. Math. 282 (2004), 149-161.
D. Newman, Problem E3274, Amer. Math. Monthly, 95 (1988), 555.
FORMULA
From Antti Karttunen, Jan 18 2016: (Start)
a(n) = A004001(n+1) - A004001(n).
Other identities. For all n >= 1:
a(A087686(n+1)-1) = 0.
a(A088359(n)-1) = 1.
a(n) = 1 if and only if A051135(n+1) = 1.
(End)
MATHEMATICA
a[1] = a[2] = 1; a[n_] := a[n] = a[a[n - 1]] + a[n - a[n - 1]]; t = Table[a[n], {n, 110}]; Drop[t, 1] - Drop[t, -1] (* Robert G. Wilson v, May 28 2004 *)
PROG
(PARI) {m=106; v=vector(m, j, 1); for(n=3, m, a=v[v[n-1]]+v[n-v[n-1]]; v[n]=a); for(n=2, m, print1(v[n]-v[n-1], ", "))}
(Scheme) (define (A093879 n) (- (A004001 (+ 1 n)) (A004001 n))) ;; Code for A004001 given in that entry. - Antti Karttunen, Jan 18 2016
CROSSREFS
Sequence in context: A108737 A165221 A295891 * A117872 A291291 A324681
KEYWORD
nonn,easy
AUTHOR
N. J. A. Sloane, May 27 2004
EXTENSIONS
More terms and PARI code from Klaus Brockhaus and Robert G. Wilson v, May 27 2004
STATUS
approved

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Last modified April 27 14:12 EDT 2024. Contains 372019 sequences. (Running on oeis4.)