|
|
A077483
|
|
Probability P(n) of the occurrence of a 2D self-trapping walk of length n: Numerator.
|
|
5
|
|
|
2, 5, 31, 173, 1521, 1056, 16709, 184183, 1370009, 474809, 13478513, 150399317, 1034714947, 2897704261
(list;
graph;
refs;
listen;
history;
text;
internal format)
|
|
|
OFFSET
|
7,1
|
|
COMMENTS
|
A comparison of the exact probabilities with simulation results obtained for 1.2*10^10 random walks is given under "Results of simulation, comparison with exact probabilities" in the first link. The behavior of P(n) for larger values of n is illustrated in "Probability density for the number of steps before trapping occurs" at the same location. P(n) has a maximum for n=31 (P(31)~=1/85.01) and drops exponentially for large n (P(800)~=1/10^9). The average walk length determined by the numerical simulation is sum n=7..infinity (n*P(n))=70.7598+-0.001
|
|
REFERENCES
|
Alexander Renner: Self avoiding walks and lattice polymers. Diplomarbeit University of Vienna, December 1994
More references are given in the sci.math NG posting in the second link
|
|
LINKS
|
|
|
FORMULA
|
P(n) = a077483(n) / ( 3^(n-1) * 2^a077484(n) )
|
|
EXAMPLE
|
A077483(10)=173 and A077484(10)=1 because there are 4 different probabilities for the 50 (=2*A077482(10)) walks: 4 walks with probability p1=1/6561, 14 walks with p2=1/8748, 22 walks with p3=1/13122, 10 walks with p4=1/19683. The sum of all probabilities is P(10) = 4*p1+14*p2+22*p3+10*p4 = (12*4+9*14+6*22+4*10)/78732 = 346/78732 = 173 / (3^9 * 2^1)
|
|
PROG
|
(Fortran) c Program provided at first link
|
|
CROSSREFS
|
|
|
KEYWORD
|
frac,more,nonn,walk
|
|
AUTHOR
|
|
|
STATUS
|
approved
|
|
|
|