A001946 a(n) = 11*a(n-1) + a(n-2). (Formerly M2009 N0794)

2, 11, 123, 1364, 15127, 167761, 1860498, 20633239, 228826127, 2537720636, 28143753123, 312119004989, 3461452808002, 38388099893011, 425730551631123, 4721424167835364, 52361396397820127, 580696784543856761, 6440026026380244498, 71420983074726546239

Offset

0,1

Comments

For odd n there is the Aurifeuillian factorization a(n) = Lucas[5n] = Lucas[n]*A[n]*B[n] = A000032[n]*A124296[n]*A124297[n], where A[n] = A124296[n] = 5*F(n)^2 - 5*F(n) + 1 and B[n] = A124297[n] = 5*F(n)^2 + 5*F(n) + 1, where F(n) = Fibonacci[n]. The largest prime divisors of a(n) for n>0 are listed in A121171[n] = {11, 41, 31, 2161, 151, 2521, 911, ...}. - Alexander Adamchuk, Oct 25 2006

For more information about this type of recurrence follow the Khovanova link and see A086902 and A054413. - Johannes W. Meijer, Jun 12 2010

References

J. Riordan, Combinatorial Identities, Wiley, 1968, p. 139.

N. J. A. Sloane, A Handbook of Integer Sequences, Academic Press, 1973 (includes this sequence).

N. J. A. Sloane and Simon Plouffe, The Encyclopedia of Integer Sequences, Academic Press, 1995 (includes this sequence).

Links

T. D. Noe, Table of n, a(n) for n = 0..200

Tanya Khovanova, Recursive Sequences

Simon Plouffe, Approximations de séries génératrices et quelques conjectures, Dissertation, Université du Québec à Montréal, 1992; arXiv:0911.4975 [math.NT], 2009.

Simon Plouffe, 1031 Generating Functions, Appendix to Thesis, Montreal, 1992

Index entries for recurrences a(n) = k*a(n - 1) +/- a(n - 2)

Index entries for linear recurrences with constant coefficients, signature (11, 1).

Formula

a(n) = Lucas(5n) = Fibonacci(5n-1) + Fibonacci(5n+1). - Alexander Adamchuk, Oct 25 2006

a(n) = ((11 + 5*sqrt(5))/2)^n + ((11 - 5*sqrt(5))/2)^n. - Tanya Khovanova, Feb 06 2007

Contribution from Johannes W. Meijer, Jun 12 2010: (Start)

a(2n+1) = 11*A097842(n), a(2n) = A065705(n).

a(3n+1) = A041226(5n), a(3n+2) = A041226(5n+3), a(3n+3) = 2* A041226(5n+4).

Limit(a(n+k)/a(k), k=infinity) = (A001946(n) + A049666(n)*sqrt(125))/2.

Limit(A001946(n)/A049666(n), n=infinity) = sqrt(125). (End)

From Peter Bala, Mar 22 2015: (Start)

a(n) = Fibonacci(10*n)/Fibonacci(5*n) for n >= 1.

a(n) = ( Fibonacci(5*n + 2*k) - F(5*n - 2*k) )/Fibonacci(2*k) for nonzero integer k.

a(n) = ( Fibonacci(5*n + 2*k + 1) + F(5*n - 2*k - 1) )/Fibonacci(2*k + 1) for arbitrary integer k.

a(n) = Sum_{k = 0..2*n} binomial(2*n,k)*Lucas(n + k). (End)

a(n) = [x^n] ( (1 + 11*x + sqrt(1 + 22*x + 125*x^2))/2 )^n for n >= 1. - Peter Bala, Jun 26 2015

Maple

A001946:=(-2+11*z)/(-1+11*z+z**2); # Conjectured by Simon Plouffe in his 1992 dissertation

Mathematica

Table[Fibonacci[5n-1]+Fibonacci[5n+1], {n, 0, 30}] (* Alexander Adamchuk, Oct 25 2006 *)
LinearRecurrence[{11, 1}, {2, 11}, 20] (* Harvey P. Dale, Jan 25 2024 *)

Prog

(Magma) [ Lucas(5*n) : n in [0..100]]; // Vincenzo Librandi, Apr 14 2011

Crossrefs

Cf. A000032, A000045, A121171, A124296, A124297.

Sequence in context: A354978 A247736 A155928 * A121337 A269069 A361036

Adjacent sequences: A001943 A001944 A001945 * A001947 A001948 A001949

Keyword

easy,nonn

Author

N. J. A. Sloane, Simon Plouffe

Status

approved