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%I #8 Mar 02 2024 10:37:50
%S 1,2,5,15,50,176,638,2351,8735,32523,120707,444218,1611211,5714056,
%T 19578953,63495983,186784641,442718804,396470087,-4588483661,
%U -45923198497,-305945783479,-1761810468901,-9395726622973,-47743575327196,-234512941253088,-1122653095777562
%N Expansion of (1/x) * Series_Reversion( x/(x+1/(1-x+x^4)) ).
%H <a href="/index/Res#revert">Index entries for reversions of series</a>
%F a(n) = Sum_{k=0..n} binomial(n,k) * b(k), where g.f. B(x) = Sum_{k>=0} b(k)*x^k satisfies B(x) = (1/x) * Series_Reversion( x*(1-x+x^4) ).
%o (PARI) my(N=30, x='x+O('x^N)); Vec(serreverse(x/(x+1/(1-x+x^4)))/x)
%Y Cf. A370799, A370800.
%Y Cf. A063028.
%K sign
%O 0,2
%A _Seiichi Manyama_, Mar 02 2024
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