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A366156
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Triangular array read by rows: T(n,k) = number of pairs u,v of partitions of n such that d(u,v) = 2k, where d is the distance function defined in Comments.
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11
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1, 2, 1, 5, 4, 1, 9, 7, 4, 1, 17, 20, 11, 6, 1, 28, 35, 22, 13, 6, 1, 47, 70, 53, 35, 17, 8, 1, 73, 119, 104, 68, 41, 21, 8, 1, 114, 211, 197, 158, 87, 58, 25, 10, 1, 170, 337, 349, 282, 185, 111, 66, 29, 10, 1, 253, 555, 626, 560, 385, 267, 143, 89, 35, 12, 1
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OFFSET
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2,2
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COMMENTS
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Suppose that p = [p(1),...,p(i)] and q = [q(1),...,q(j)] are partitions of n, where p(1) >= ... >= p(i) and q(1) >= ... >= q(j). If i = n, let p_ = p, else p_ = [p(1),...,p(i),0,...,0], where the number of 0' s appended is n-i. If j = n, let q_ = q, else q_ = [q(1),...,q(j),0,...,0], where the number of 0's appended is n-j. Write p_ = [p(1),...,p(i),p(i+1),...,p(n)] and q_ = [q(1),...,q(j),q(j+1),...,q(n)]. The distance between p and q is defined by d(p,q) = |p(1) - q(1)| + ... + |p(n) - q(n)|.
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LINKS
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EXAMPLE
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Write the 5 partitions of 4 as 4, 31, 22, 211, 111, and represent them as a,b,c,d,e in the following tableaux:
a : 4 0 0 0 | 2 4 4 6
b : 3 1 0 0 | 2 2 4
c : 2 2 0 0 | 2 4
d : 2 1 1 0 | 2
e : 1 1 1 1
where, for example, the distances 2 4 4 6 are given by
d(a,b) = |4-3| + |0-1| + |0-0| + |0-0| = 2
d(a,c) = |4-2| + |0-2| + |0-0| + |0-0| = 4
d(a,d) = |4-2| + |0-1| + |0-1| + |0-0| = 4
d(a,e) = |4-1| + |0-1| + |0-1| + |0-1| = 6
First eight rows:
1
2 1
5 4 1
9 7 4 1
17 20 11 6 1
28 35 22 13 6 1
47 70 53 35 17 8 1
73 119 104 68 41 21 8 1
...
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MATHEMATICA
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c[n_] := PartitionsP[n];
q[n_, k_] := q[n, k] = IntegerPartitions[n][[k]];
r[n_, k_] := r[n, k] = Join[q[n, k], ConstantArray[0, n - Length[q[n, k]]]];
d[u_, v_] := Total[Abs[u - v]];
t[n_] := Flatten[Table[d[r[n, j], r[n, k]], {j, 1, -1 + c[n]}, {k, j + 1, c[n]}]];
t1 = Table[Count[t[n], m], {n, 2, 17}, {m, 2, 2 n - 2, 2}]
TableForm[t1] (* this sequence as an array *)
u = Flatten[t1] (* this sequence *)
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CROSSREFS
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KEYWORD
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AUTHOR
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STATUS
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approved
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