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A321667
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(3/2) * n^(2/3) rounded to nearest integer.
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2
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2, 2, 3, 4, 4, 5, 5, 6, 6, 7, 7, 8, 8, 9, 9, 10, 10, 10, 11, 11, 11, 12, 12, 12, 13, 13, 14, 14, 14, 14, 15, 15, 15, 16, 16, 16, 17, 17, 17, 18, 18, 18, 18, 19, 19, 19, 20, 20, 20, 20, 21, 21, 21, 21, 22, 22, 22, 22, 23, 23, 23, 23, 24, 24, 24, 24, 25, 25, 25, 25, 26, 26, 26, 26, 27
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OFFSET
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1,1
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COMMENTS
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This is an approximation to the solution of the "Concrete Math Club" casino problem given in A079631.
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REFERENCES
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R. L. Graham, D. E. Knuth and O. Patashnik, Concrete Mathematics. 2nd Edition. Addison-Wesley, Reading, MA, 1994. Section 3.2, pp. 74-76.
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LINKS
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MATHEMATICA
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a[n_]:=Round[(3/2)*n^(2/3)]; Array[a, 50] (* Stefano Spezia, Nov 16 2018 *)
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PROG
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(PARI) for(j=1, 75, print1(round(1.5*j^(2/3)), ", "))
(Python) for n in range(1, 50): print(round((3/2)*n**(2/3)), end=', ') # Stefano Spezia, Nov 16 2018
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CROSSREFS
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KEYWORD
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nonn,easy
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AUTHOR
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STATUS
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approved
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