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A309949 Decimal expansion of the imaginary part of the square root of 1 + i. 3
4, 5, 5, 0, 8, 9, 8, 6, 0, 5, 6, 2, 2, 2, 7, 3, 4, 1, 3, 0, 4, 3, 5, 7, 7, 5, 7, 8, 2, 2, 4, 6, 8, 5, 6, 9, 6, 2, 0, 1, 9, 0, 3, 7, 8, 4, 8, 3, 1, 5, 0, 0, 9, 2, 5, 8, 8, 2, 5, 9, 5, 6, 9, 4, 9, 0, 8, 0, 0, 2, 0, 3, 2, 3, 3, 4, 4, 8, 2, 9, 1, 5, 9, 1, 4, 0, 1, 8, 1, 9, 7, 6, 1, 0, 2 (list; constant; graph; refs; listen; history; text; internal format)
OFFSET
0,1
COMMENTS
i is the imaginary unit such that i^2 = -1.
Multiplied by -1, this is the imaginary part of the square root of 1 - i. And also the real part of -sqrt(1 + i) - i + sqrt(1 + i)^3, which is a unit in Q(sqrt(1 + i)).
LINKS
FORMULA
Equals sqrt(1/sqrt(2) - 1/2) = 2^(1/4) * sin(Pi/8).
Equals sqrt((sqrt(2) - 1)/2) = A010767 * A182168. - Bernard Schott, Sep 16 2019
Equals Re(sqrt(-1 - i)). - Peter Luschny, Sep 20 2019
Equals Product_{k>=0} ((8*k - 1)*(8*k + 4))/((8*k - 2)*(8*k + 5)). - Antonio Graciá Llorente, Feb 24 2024
EXAMPLE
Im(sqrt(1 + i)) = 0.45508986056222734130435775782247...
MAPLE
Digits := 120: Re(sqrt(-1 - I))*10^95:
ListTools:-Reverse(convert(floor(%), base, 10)); # Peter Luschny, Sep 20 2019
MATHEMATICA
RealDigits[Sqrt[1/Sqrt[2] - 1/2], 10, 100][[1]]
PROG
(PARI) imag(sqrt(1+I)) \\ Michel Marcus, Sep 16 2019
CROSSREFS
Cf. A000108, A010767, A182168, A309948 (real part).
Sequence in context: A247860 A196756 A103561 * A198571 A119822 A120651
KEYWORD
nonn,cons,easy
AUTHOR
Alonso del Arte, Aug 24 2019
STATUS
approved

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Last modified April 30 00:54 EDT 2024. Contains 372115 sequences. (Running on oeis4.)