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A242397 a(n) is the number of different bases b such that the Brazilian numbers A125134(n) remain a repdigit number. 3
1, 1, 1, 1, 1, 1, 2, 1, 2, 1, 2, 1, 3, 2, 1, 2, 2, 2, 2, 1, 1, 1, 3, 1, 1, 4, 3, 1, 2, 2, 1, 4, 2, 1, 2, 3, 1, 2, 2, 1, 5, 2, 4, 2, 1, 3, 2, 1, 3, 4, 1, 1, 2, 2, 1, 3, 5, 1, 1, 5, 2, 2, 1, 3, 4, 2, 2, 2, 1, 1, 5, 2, 2, 3, 3, 3, 3, 1, 5, 2, 2, 4, 4, 1, 2, 2, 1 (list; graph; refs; listen; history; text; internal format)
OFFSET
1,7
COMMENTS
For all numbers m, we restrict the bases b with 1 < b < m-1 because m is repdigit in bases 1 and also m-1.
LINKS
EXAMPLE
a(89) = 7 because A125134(89)=120 and the number 120 is AA in base 11 where A = 10, 88 in base 14, 66 in base 19, 55 in base 23, 44 in base 29, 33 in base 39 and 22 in base 59 => 7 representations.
MAPLE
for n from 1 to 200 do:c:=0:for b from 2 to n-2 do:x:=convert(n, base, b):n1:=nops(x):a:=x[n1]:i:=1:for k from n1-1 by -1 to 1 do:if x[k]=a then i:=i+1:else fi:od:if i=n1 then c:=c+1:i:=1:else fi:od:if c>0 then printf(`%d, `, c):else fi:od:
CROSSREFS
Sequence in context: A316384 A029838 A213649 * A023132 A023124 A023120
KEYWORD
nonn,base
AUTHOR
Michel Lagneau, May 13 2014
STATUS
approved

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Last modified June 11 14:45 EDT 2024. Contains 373311 sequences. (Running on oeis4.)