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A173298
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Integers n >= 2 such that the ring Z(sqrt n) is not factorial.
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1
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5, 8, 10, 12, 13, 15, 17, 18, 20, 21, 24, 26, 27, 28, 29, 30, 32, 33, 35, 37, 39, 40, 41, 42, 44, 45, 48, 50, 52, 53, 54, 55, 56, 57, 58, 60, 61, 63, 65, 68, 69, 70, 72, 73, 74, 75, 76, 77, 78, 80, 82, 84, 85, 87, 88, 89, 90, 91, 92, 93, 95, 96, 97, 98, 99, 101, 103
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OFFSET
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1,1
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COMMENTS
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A factorial ring is an integral domain in which one can find a system of irreducible elements P such that every nonzero element admits a unique representation. We consider the ring Z(sqrt n), where n >=2 such that this ring is not factorial. It is well known that the ring Z(sqrt n) is not factorial if it satisfies the following conditions: n == 1 mod 4, n has a square divisor different of 1 and the number 2 is irreducible in Z(sqrt n). In consequence, the equation x^2 - ny^2 = -2 or +2 has no solution.
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REFERENCES
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R. Dedekind, Sur la théorie des nombres entiers algébriques, Gauthier-Villars, 1877. English translation with an introduction by J. Stillwell: Theory of Algebraic Integers, Cambridge Univ. Press, 1996.
W. Krull, Idealtheorie, Springer Verlag, 1937 (2e edition 1968)
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LINKS
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FORMULA
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We calculate n from the conditions : n == 1 mod. 4, or n has a square integer which divides n, or the equation x^2 - ny^2 = -2 or +2 has no solution.
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EXAMPLE
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For n = 3, n == 3 (mod 4) and no square divide 3. The solutions of the equation x^2 - 3y^2 = -2 or +2 are x = 1 (or -1), y = 1 (or -1). The ring Z(sqrt 3) is factorial.
For n = 5, n == 1 (mod 4), the ring Z(sqrt 5) is not factorial.
For n = 87, n == 3 (mod 4) and no square divide 87, but the equation x^2 - 87y^2 = -2 or +2 has no solution. The ring Z(sqrt 87) is not factorial.
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MATHEMATICA
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lst={}; Do[ii=0; Do[If[IntegerQ[Sqrt[n*x^2+2]]||IntegerQ[Sqrt[n*x^2-2]], ii=1], {x, 2, 10^5}]; If[!IntegerQ[Sqrt[n]]&&(ii==0||Mod[n, 4]==1||!SquareFreeQ[n]), AppendTo[lst, n]], {n, 2, 100}]; lst (* Michel Lagneau, Dec 18 2018 *)
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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