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A171749
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Odd primes of the form (1+n)*(2+2*n)+n*(3+2*n) = 4*n^2+7*n+2.
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2
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13, 59, 137, 389, 563, 769, 1277, 1579, 1913, 2677, 5147, 5737, 6359, 7013, 7699, 9949, 12487, 13397, 15313, 16319, 18427, 20663, 23027, 26813, 32309, 36767, 38317, 41513, 43159, 51869, 61379, 63377, 65407, 73847, 78259, 80513, 82799, 89849
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OFFSET
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1,1
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COMMENTS
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Also primes of the form 16*m^2-2*m-1, by the substitution n=2*m-1. [Note that n is odd because otherwise 4n^2+7n+2 is even]. - Bruno Berselli, Jul 03 2012
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LINKS
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MATHEMATICA
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f[n_] := (1+n)(2+2*n)+n*(3+2*n); lst={}; Do[If[PrimeQ[f[n]], AppendTo[lst, f[n]]], {n, 6!}]; lst
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CROSSREFS
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KEYWORD
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nonn,easy
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AUTHOR
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STATUS
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approved
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