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A140362
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Semiprimes pq that divide the sum of the squares of their divisors, 1+p^2+q^2+(pq)^2.
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4
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OFFSET
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1,1
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COMMENTS
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6 is the smallest integer n which is the product of two distinct primes and which divides the sum of the cubes of the divisors of n. Are there other numbers with this property?
Using Pell equations and a Fibonacci identity, Max Alekseyev and I have shown that all terms are the product of prime Fibonacci numbers whose indices are twin primes. The first three terms are Fib(3)*Fib(5), Fib(5)*Fib(7) and Fib(11)*Fib(13). The other two known terms are Fib(431)*Fib(433) and Fib(569)*Fib(571), huge numbers that are in the b-file. The sequence probably has no additional terms. - T. D. Noe, Jul 27 2008
Let a, b, c and d be consecutive odd-indexed Fibonacci numbers. Then it can be proved that 1 + b^2 + c^2 + (bc)^2 = abcd, which shows that bc divides 1 + b^2 + c^2 + (bc)^2. Hence if b and c are prime, then bc is in this sequence. - T. D. Noe, Jul 27 2008
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LINKS
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EXAMPLE
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10 divides (1^2 + 2^2 + 5^2).
65 divides (1^2 + 5^2 + 13^2).
20737 divides (1^2 + 89^2 + 233^2).
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PROG
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(PARI) isok(n) = sigma(n, 2) - n^2 == 3*n; \\ Michel Marcus, Jun 24 2014
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CROSSREFS
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KEYWORD
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nonn,bref
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AUTHOR
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STATUS
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approved
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