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A127675 Coefficient table for Chebyshev's U(2*n,x) polynomials in decreasing powers of (1-x^2). 3
1, -4, 3, 16, -20, 5, -64, 112, -56, 7, 256, -576, 432, -120, 9, -1024, 2816, -2816, 1232, -220, 11, 4096, -13312, 16640, -9984, 2912, -364, 13, -16384, 61440, -92160, 70400, -28800, 6048, -560, 15, 65536, -278528, 487424, -452608, 239360, -71808, 11424, -816, 17, -262144, 1245184 (list; table; graph; refs; listen; history; text; internal format)
OFFSET
0,2
COMMENTS
This table gives therefore sin((2*n+1)*phi) in terms of falling odd powers of sin(phi).
The unsigned triangle with reversed rows is A084930 (the signs differ).
LINKS
FORMULA
a(n,m)=0 if n < m else a(n,m) = ((-4)^(n-m))*binomial(2n-m,m)*(2*n+1)/(2*(n-m)+1), n >= m >= 0. (Proof from the differential eq. for U(2*n,x): (1-x^2)*(d^2/dx^2)U(2*n,x) - 3*x*(d/dx)U(2*n,x) + 4*n*(n+1)*U(2*n,x) = 0.)
a(n,m)=0 if n < m else a(n,m) = Sum_{k=0..n-m} (binomial(m+k,k)*binomial(2*n+1,2*(m+k))*(-1)^(n-m)) (from de Moivre's formula for sin((2*n+1)*phi) after replacing cos(phi)^2 with 1-sin(phi)^2).
EXAMPLE
[1];[ -4,3];[16,-20,5];[ -64,112,-56,7];[256,-576,432,-120,9]; ...
Row n=3: -64*(1-x^2)^3+ 112*(1-x^2)^2 -56*(1-x^2)^1 + 7 = 64*x^6 - 80*x^4 + 24* x^2 -1 =U(6,x).
Row n=3: sin(7*phi)=-64*sin(phi)^7 + 112*sin(phi)^5 - 56*sin(phi)^3 + 7*sin(phi).
CROSSREFS
Row sums (signed) A033999(n)=(-1)^n. Row sums (unsigned) A002315(n).
Cf. A082985 (scaled coefficient table).
Sequence in context: A285646 A092398 A288199 * A058557 A287978 A288368
KEYWORD
sign,tabl,easy
AUTHOR
Wolfdieter Lang, Mar 07 2007
STATUS
approved

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Last modified April 28 15:29 EDT 2024. Contains 372088 sequences. (Running on oeis4.)