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%I #6 Mar 31 2012 13:20:34
%S 1,3,9,105,306,3567,10395,121173,353124,4116315,11995821,139833537,
%T 407504790,4750223943,13843167039,161367780525,470260174536,
%U 5481754313907,15975002767185,186218278892313,542679833909754
%N Numbers m such that m^2=A125650(k) for some k (belonging A125651).
%C Indices k such that a(n)^2=A125650(k) are listed in A125651.
%C 3 divides a(n) for n>1. For n>1 a(n) = 3*A041053(2n-3), where A041053(n) = {1, 1, 2, 3, 32, 35, 67, 102, 1087, 1189, 2276, 3465, ...} Denominators of continued fraction convergents to sqrt(32). - _Alexander Adamchuk_, Jan 19 2007
%F a(2k)=A106328(2k); for k>0, a(2k+1)=A106328(2k+1)/2.
%F a(n) = sqrt(A125650(A125651(n))).
%F a(n) = 3*A041053(2n-3) for n>1. - _Alexander Adamchuk_, Jan 19 2007
%e a(2)=3 because A125650(3)=9=3^2; a(3)=9 because A125650(24)=81=9^2.
%Y Cf. A125650, A125651, A106328.
%Y Cf. A041053.
%K nonn
%O 1,2
%A _Alexander Adamchuk_, Nov 29 2006, corrected Dec 14 2006
%E Edited by _Max Alekseyev_, Jan 11 2007
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