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A125650 Numerator of n(n+3)/(4(n+1)(n+2)) = sum(k=1..n, 1/(k(k+1)(k+2)) ). 10

%I #37 Sep 08 2022 08:45:28

%S 0,1,5,9,7,5,27,35,11,27,65,77,45,26,119,135,38,85,189,209,115,63,275,

%T 299,81,175,377,405,217,116,495,527,140,297,629,665,351,185,779,819,

%U 215,451,945,989,517,270,1127,1175,306,637,1325,1377,715,371,1539,1595,413,855

%N Numerator of n(n+3)/(4(n+1)(n+2)) = sum(k=1..n, 1/(k(k+1)(k+2)) ).

%C 3^2 divides a(3k). p divides a(p) for an odd prime p. p divides a(p-3) for prime p>3. p^k divides a(p^k) for an odd prime p. a(n) = m^2 is a perfect square for n = {1,3,24,147,864,5043,29400,171363,...} = A125651(n). Corresponding numbers m such that m^2 = a[ A125651(n) ] are listed in A125652(n) = {1,3,9,105,306,3567,10395,121173,...}.

%D L. B.W. Jolley, Summation of Series, Second revised ed., Dover, 1961, p.38, (201).

%H Vincenzo Librandi, <a href="/A125650/b125650.txt">Table of n, a(n) for n = 0..1000</a>

%F a(n) = Sum_{k=1..n} 1/(k(k+1)(k+2)).

%F a(n) = n*(n+3)/2^min(3,valuation(n*(n+3),2)). a(n)=n*(n+3)/4 for n=1 or 4 (mod 8); a(n)=n*(n+3)/8 for n=0 or 5 (mod 8); a(n) = n*(n+3)/2 for n=2, 3, 6, or 7 (mod 8). - _Max Alekseyev_, Jan 11 2007

%F a(n) = A106609(n)*A106609(n+3). - _Paul Curtz_, Jan 13 2011

%F G.f.: x*(x^19 -2*x^18 +3*x^17 -5*x^16 +3*x^15 -6*x^14 +7*x^13 -11*x^12 -12*x^11 +24*x^10 -36*x^9 +24*x^8 -38*x^7 +28*x^6 -18*x^5 -3*x^4 -2*x -1) / ((x-1)^3*(x^2+1)^3*(x^4+1)^3). - _Colin Barker_, Feb 21 2013

%F G.f. for rationals r(n) = a(n)/A230328(n): (1/4)*(1 - hypergeometric([1, 2], [3], -x/(1-x)))/(1-x) = (- 2*x + 3*x^2 + 2*(2*x - (1 + x^2))*log(1-x))/(4*(1-x)*x^2). For the r(n) formula see Jolley's general remark (201) on p.38. Thanks to Gary Detlefs for pointing to this remark. - _Wolfdieter Lang_, Mar 08 2018

%e The rationals n(n+3)/(4(n+1)(n+2)) = a(n)/A230328(n) begin:

%e 0, 1/6, 5/24, 9/40, 7/30, 5/21, 27/112, 35/144, 11/45, 27/110, 65/264, 77/312, 45/182, 26/105, 119/480, ... - _Wolfdieter Lang_, Mar 08 2018

%t Table[Numerator[n(n+3)/(4(n+1)(n+2))],{n,0,100}]

%o (PARI) a(n)=n*(n+3)/2^min(3,valuation(n*(n+3),2)); \\ _Max Alekseyev_, Jan 11 2007

%o (Magma) [Numerator(n*(n+3)/(4*(n+1)*(n+2))): n in [0..60]]; // _Vincenzo Librandi_, May 21 2012

%Y Cf. A125651, A125652. A160050, A230328 (denominators).

%K nonn,frac,easy

%O 0,3

%A _Alexander Adamchuk_, Nov 29 2006

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