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A122043 Rotations of 123, 245, 367, 489 (terms differ by 122) juxtaposed with the product of their last 2 digits. See example line. 0

%I #4 Dec 10 2015 02:35:15

%S 1236,3122,2313,24520,5248,45210,36742,73618,67321,48972

%N Rotations of 123, 245, 367, 489 (terms differ by 122) juxtaposed with the product of their last 2 digits. See example line.

%H Sergio Silva, <a href="http://ginasiomental.no.sapo.pt/materialc/mteste/teste.htm">Teste Numerico</a>.

%e a(1) = 1236 because we can write 123 juxtaposed with the product of its last 2 digits: 2*3=6.

%e a(2) = 3122 because we can write 312 (counterclockwise rotation of 123) juxtaposed with the product of its last 2 digits: 1*2=2.

%e a(3) = 2313 because we can write 231 (counterclockwise rotation of 312) juxtaposed with the product of its last 2 digits: 3*1=3.

%e Once finished '123' rotations:

%e a(4) = 24520 because we can write 245 (123+122) juxtaposed with the product of its last 2 digits: 4*5=20.

%e a(5) = 5248 because we can write 524 (counterclockwise rotation of 245) juxtaposed with the product of its last 2 digits: 2*4=8.

%e a(6) = 45210 because we can write 452 (counterclockwise rotation of 524) juxtaposed with the product of its last 2 digits: 5*2=10.

%e Once finished '245' rotations:

%e a(7) = 36742 because we can write 367 (245+122) juxtaposed with the product of its last 2 digits: 6*7=42

%e a(8) = 73618 because we can write 736 (counterclockwise rotation of 367) juxtaposed with the product of its last 2 digits: 3*6=18.

%e a(9) = 67321 because we can write 673 (counterclockwise rotation of 736) juxtaposed with the product of its last 2 digits: 7*3=21.

%e Once finished '367' rotations:

%e a(10) = 48972 because we can write 489 (367+122) juxtaposed with the product of its last 2 digits: 8*9=72.

%K base,nonn

%O 1,1

%A Herman Jamke (hermanjamke(AT)fastmail.fm), Oct 15 2006

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