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A116931
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Number of partitions of n in which each part, with the possible exception of the largest, occurs at least twice.
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19
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1, 2, 2, 4, 4, 8, 8, 13, 15, 22, 24, 37, 40, 57, 64, 89, 98, 135, 149, 199, 224, 292, 325, 424, 472, 601, 676, 850, 950, 1191, 1329, 1643, 1845, 2258, 2524, 3082, 3442, 4158, 4659, 5591, 6246, 7472, 8338, 9903, 11072, 13077, 14586, 17184, 19150, 22431, 25019
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OFFSET
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1,2
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COMMENTS
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Also, partitions of n in which any two distinct parts differ by at least 2. Example: a(5) = 4 because we have [5], [4,1], [3,1,1] and [1,1,1,1,1].
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REFERENCES
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P. A. MacMahon, Combinatory Analysis, Cambridge Univ. Press, London and New York, Vol. 1, 1915 and Vol. 2, 1916; see vol. 2, p 52, Article 298.
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LINKS
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FORMULA
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G.f.: sum(x^k*product(1+x^(2j)/(1-x^j), j=1..k-1)/(1-x^k), k=1..infinity). More generally, the g.f. of partitions of n in which each part, with the possible exception of the largest, occurs at least b times, is sum(x^k*product(1+x^(bj)/(1-x^j), j=1..k-1)/(1-x^k), k=1..infinity). It is also the g.f. of partitions of n in which any two distinct parts differ by at least b.
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EXAMPLE
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a(5) = 4 because we have [5], [3,1,1], [2,1,1,1] and [1,1,1,1,1].
q + 2*q^2 + 2*q^3 + 4*q^4 + 4*q^5 + 8*q^6 + 8*q^7 + 13*q^8 + 15*q^9 + ...
There are a(9) = 15 partitions of 9 where distinct parts differ by at least 2:
01: [ 1 1 1 1 1 1 1 1 1 ]
02: [ 3 1 1 1 1 1 1 ]
03: [ 3 3 1 1 1 ]
04: [ 3 3 3 ]
05: [ 4 1 1 1 1 1 ]
06: [ 4 4 1 ]
07: [ 5 1 1 1 1 ]
08: [ 5 2 2 ]
09: [ 5 3 1 ]
10: [ 6 1 1 1 ]
11: [ 6 3 ]
12: [ 7 1 1 ]
13: [ 7 2 ]
14: [ 8 1 ]
15: [ 9 ]
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MAPLE
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g:=sum(x^k*product(1+x^(2*j)/(1-x^j), j=1..k-1)/(1-x^k), k=1..70): gser:=series(g, x=0, 60): seq(coeff(gser, x^n), n=1..54);
# second Maple program:
b:= proc(n, i) option remember; `if`(n=0, 1, `if`(i<1, 0,
b(n, i-1) +add(b(n-i*j, i-2), j=1..n/i)))
end:
a:= n-> b(n, n):
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MATHEMATICA
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b[n_, i_] := b[n, i] = If[n==0, 1, If[i<1, 0, b[n, i-1] + Sum[b[n-i*j, i-2], {j, 1, n/i}]]]; a[n_] := b[n, n]; Table[a[n], {n, 1, 70}] (* Jean-François Alcover, Mar 24 2015, after Alois P. Heinz *)
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PROG
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(PARI) {a(n) = if( n<1, 0, polcoeff( sum( k=1, n, x^k / (1 - x^k) * prod( j=1, k-1, 1 + x^(2*j) / (1 - x^j), 1 + x * O(x^(n-k)))), n))} /* Michael Somos, Jan 26 2008 */
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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