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A110510
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Riordan array (1, x*c(2x)), c(x) the g.f. of A000108.
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6
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1, 0, 1, 0, 2, 1, 0, 8, 4, 1, 0, 40, 20, 6, 1, 0, 224, 112, 36, 8, 1, 0, 1344, 672, 224, 56, 10, 1, 0, 8448, 4224, 1440, 384, 80, 12, 1, 0, 54912, 27456, 9504, 2640, 600, 108, 14, 1, 0, 366080, 183040, 64064, 18304, 4400, 880, 140, 16, 1, 0, 2489344, 1244672, 439296
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OFFSET
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0,5
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COMMENTS
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Triangle T(n,k), 0 <= k <= n, read by rows, given by (0, 2, 2, 2, 2, 2, 2, 2, ...) DELTA (1, 0, 0, 0, 0, 0, 0, 0, ...) where DELTA is the operator defined in A084938. - Philippe Deléham, Sep 23 2014
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LINKS
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FORMULA
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Number triangle: T(0,k) = 0^k, T(n,k) = (k/n)*C(2n-k-1, n-k)*2^(n-k), n, k > 0.
T(n,k) = 2*T(n,k+1) + T(n-1,k-1) with T(n,n) = 1 and T(n,0) = 0 for n >= 1. - Peter Bala, Feb 02 2020
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EXAMPLE
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Rows begin
1;
0, 1;
0, 2, 1;
0, 8, 4, 1;
0, 40, 20, 6, 1;
0, 224, 112, 36, 8, 1;
...
Production matrix begins:
0, 1;
0, 2, 1;
0, 4, 2, 1;
0, 8, 4, 2, 1;
0, 16, 8, 4, 2, 1;
0, 32, 16, 8, 4, 2, 1;
0, 64, 32, 16, 8, 4, 2, 1;
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MATHEMATICA
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T[n_, k_] := (k/n)*Binomial[2*n - k - 1, n - k]*2^(n - k); Join[{1}, Table[T[n, k], {n, 1, 10}, {k, 0, n}]] // Flatten (* G. C. Greubel, Aug 29 2017 *)
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PROG
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(PARI) concat([1], for(n=1, 25, for(k=0, n, print1((k/n)*binomial(2*n-k-1, n-k)*2^(n-k), ", ")))) \\ G. C. Greubel, Aug 29 2017
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CROSSREFS
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KEYWORD
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AUTHOR
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STATUS
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approved
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