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A110237
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Triangle read by rows: T(n,k) (0 <= k <= ceiling(n/2)-1) is the number of (1,0) steps at level k in all peakless Motzkin paths of length n (can be easily translated into RNA secondary structure terminology).
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1
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1, 2, 3, 1, 6, 4, 13, 10, 1, 28, 24, 6, 62, 59, 21, 1, 140, 144, 62, 8, 320, 350, 174, 36, 1, 740, 852, 474, 128, 10, 1728, 2077, 1263, 410, 55, 1, 4068, 5072, 3318, 1240, 230, 12, 9645, 12412, 8634, 3608, 835, 78, 1, 23010, 30440, 22314, 10216, 2792, 376, 14
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OFFSET
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1,2
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COMMENTS
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Row n has ceiling(n/2) terms. Row sums yield A110236.
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LINKS
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FORMULA
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G.f.: z*g^2/(1-tz^2*g^2), where g = 1 + zg + z^2*g(g-1) = (1 - z + z^2 - sqrt(1 - 2z - z^2 - 2z^3 + z^4))/(2z^2) is the g.f. of the RNA secondary structure numbers (A004148).
T(n,m) = (m+1)*Sum_{i=0..(n-1)/2-m}((binomial(2*m+2*i+2,i)*Sum_{k=0..n-2*m-2*i-1}(binomial(k,n-2*m-k-2*i-1)*binomial(2*m+k+2*i+1,k)*(-1)^(n-k-1)))/(m+i+1)). - Vladimir Kruchinin, Mar 07 2016
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EXAMPLE
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T(5,1)=10 because in the 8 (=A004148(5)) peakless Motzkin paths of length 5, namely HHHHH, U(H)DHH, U(HH)DH, U(HHH)D, HU(H)DH, HU(HH)D, HHU(H)D and UUHDD (where U=(1,1), H=(1,0) and D=(1,-1)), we have altogether 10 H steps at level 1 (shown between parentheses).
Triangle starts:
1;
2;
3, 1;
6, 4;
13, 10, 1;
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MAPLE
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g:=(1-z+z^2-sqrt(1-2*z-z^2-2*z^3+z^4))/2/z^2: G:=z*g^2/(1-t*z^2*g^2): Gser:=simplify(series(G, z=0, 20)): for n from 1 to 15 do P[n]:=coeff(Gser, z^n) od: for n from 1 to 15 do seq(coeff(t*P[n], t^k), k=1..ceil(n/2)) od;
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PROG
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(Maxima)
T(n, m):=(m+1)*sum((binomial(2*m+2*i+2, i)*sum(binomial(k, n-2*m-k-2*i-1)*binomial(2*m+k+2*i+1, k)*(-1)^(n-k-1), k, 0, n-2*m-2*i-1))/(m+i+1), i, 0, (n-1)/2-m); /* Vladimir Kruchinin, Mar 07 2016 */
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CROSSREFS
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KEYWORD
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nonn,tabf
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AUTHOR
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STATUS
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approved
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