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A105788
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a(1) = 1; a(m) = minimum numerator possible with a continued fraction [b(1);b(2),b(3),...b(m-1)], where (b(1),b(2),b(3),...b(m-1)) is a permutation of (a(1),a(2),a(3),...a(m-1)).
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1
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1, 1, 2, 4, 16, 192, 29984, 776474136, 582837534997525192, 334033256143852482501323872038100184, 111432026121971983026248175426087984579225579894344486903683496908882296
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OFFSET
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1,3
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LINKS
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EXAMPLE
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a(6)=192 because the minimum numerator among permutations of
(1,1,2,4,16) happens when the continued fraction is [1:4,2,16,1]=192/157 or
[1:16,2,4,1]=192/181.
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MATHEMATICA
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a[1] = 1; a[n_] := a[n] = Union[ Numerator /@ FromContinuedFraction /@ Permutations[ Table[ a[i], {i, n - 1}]]] [[1]]; Table[ a[n], {n, 11}]
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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