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A105400
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Absolute values of the three roots of p^3 + 2*p^2 - (3 - b[n])*p - b[n]: b[n]=3*Prime[n]-Prime[n]^2.
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0
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2, 1, 1, 3, 0, 1, 5, 1, 2, 7, 1, 4, 11, 1, 8, 13, 1, 10, 17, 1, 14, 19, 1, 16, 23, 1, 20, 29, 1, 26, 31, 1, 28, 37, 1, 34, 41, 1, 38, 43, 1, 40, 47, 1, 44, 53, 1, 50, 59, 1, 56, 61, 1, 58, 67, 1, 64, 71, 1, 68, 73, 1, 70, 79, 1, 76, 83, 1, 80, 89, 1, 86, 97, 1, 94, 101, 1, 98, 103, 1, 100
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OFFSET
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1,1
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COMMENTS
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The maximum modulus root of this polynomial is always a prime.
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LINKS
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FORMULA
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b[n]=3*Prime[n]-Prime[n]^2 a(n) = Abs[root[i, m]]/.p^3 + 2*p^2 - (3 - b[n])*p - b[n]
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MATHEMATICA
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b= Table[3* Prime[n] - Prime[n]^2, {n, 1, Digits}] a = Abs[Flatten[Table[p /. Solve[p^3 + 2*p^2 - (3 - b[[n]])*p - b[[n]] == 0, p][[i]], {n, 1, Digits}, {i, 1, 3}]]]
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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