A094497 Triangular table A(n,j) = C(n,j) - C(n,j) mod n^3, difference of binomial coefficient and its residue mod n^3, read by rows.

1, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 2744, 2744, 2744, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 3375, 3375, 3375, 3375, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 4096, 4096, 8192, 12288, 8192, 4096, 4096

Offset

0,112

Comments

a(0) = 1 by convention.

Links

Antti Karttunen, Table of n, a(n) for n = 0..10439; the first 144 rows of triangle

Index entries for triangles and arrays related to Pascal's triangle

Example

Out of a(1)=1 and a(2)=1, the first deviation from A007318 is at a(111) because C(14,6) = 3003, 3003 mod 2744 = 259, a(111) = 2744.

Mathematica

Flatten[Table[Table[Binomial[n, j]-Mod[Binomial[n, j], n^3], {j, 0, n}], {n, 1, 14}], 1]

Crossrefs

Cf. A007318, A053200, A094495, A094496.

Sequence in context: A107570 A237680 A262819 * A202460 A262820 A262817

Adjacent sequences: A094494 A094495 A094496 * A094498 A094499 A094500

Keyword

easy,nonn,tabl

Author

Labos Elemer, Jun 02 2004

Status

approved