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A091656
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Least number k such that the continued fraction expansion of H(k) contains the numbers 1, 2, ..., n, where H(k) is the k-th Harmonic number.
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2
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1, 2, 5, 9, 9, 13, 26, 63, 68, 68, 68, 87, 121, 121, 165, 207, 207, 221, 221, 287, 289, 325, 428, 440, 483, 544, 544, 544, 544, 544, 558, 558, 558, 966, 1035, 1035, 1146, 1146, 1332, 1332, 1332, 1665, 1665, 1665, 1665, 1665, 1727, 1727, 2052, 2157, 2331, 2331
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OFFSET
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1,2
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LINKS
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EXAMPLE
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a(6) = 13 because CF( H(13)) = 3 + [5, 1, 1, 4, 2, 1, 3, 2, 1, 3, 1, 4, 1, 6], the first six integers are present.
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MATHEMATICA
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f[n_] := Block[{k = 1}, While[ StringPosition[ ToString[ Union[ ContinuedFraction[ Sum[1/i, {i, 1, k}]]]], StringDrop[ ToString[ Table[i, {i, n}]], -1]] == {}, k++ ]; k]; Table[ f[n], {n, 1, 52}]
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PROG
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(PARI) list(lim)=my(v=vector(lim\1), n, t, H, i=1); while(1, H+=1/n++; t=vecsort(contfrac(H), , 8); if(#t>=i&&t[i]==i, v[i]=n; print1(n":"i", "); if(i++>#v, return(v)); H-=1/n; n--)) \\ Charles R Greathouse IV, Jan 25 2012
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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