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A091457
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Greatest numerator of the remainder in a reciprocal expansion of 1.
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1
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OFFSET
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1,4
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COMMENTS
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Conjecture: in the "extremal" expansion x_i = A000058(i) for i=1..n-3.
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LINKS
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FORMULA
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Let 1 = 1/x_1 + ... + 1/x_{n-1} + p/q, where 1/x_1>=...>=1/x_{n-1}>=p/q and (p, q)=1. a(n) = maximal p over all such expansions. Corresponded denominators sequence is A091458.
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EXAMPLE
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a(7) = 9770455 because 1 = 1/2 + 1/3 + 1/7 + 1/43 + 1/5413 + 1/5419 + 9770455/52975482882 and there is no expansion with larger numerator of the remainder.
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CROSSREFS
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KEYWORD
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frac,hard,nonn,more
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AUTHOR
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STATUS
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approved
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