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A082240
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Break up the cyclic concatenation 1234567890123456789023... into parts nontrivially (a(n) is not equal to n) such that the n-th part is a multiple of n.
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1
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12, 34, 567, 8, 90, 12, 34567890, 123456, 789012, 34567890, 123456789012345678901
(list;
graph;
refs;
listen;
history;
text;
internal format)
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OFFSET
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1,1
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COMMENTS
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a(12) does not exist: 23 mod 12, 234 mod 12, 2345 mod 12, ... is periodic and does not contain 0. - Sam Alexander, Feb 23 2004
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LINKS
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CROSSREFS
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KEYWORD
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base,fini,full,nonn
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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