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A073361
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Nested floor product of n and fractions (k+1)/k for all k>0 (mod 4), divided by 4.
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3
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1, 5, 15, 31, 65, 105, 151, 275, 420, 631, 695, 1050, 1411, 1685, 2385, 2941, 3425, 4410, 5326, 6995, 7350, 9316, 10880
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OFFSET
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1,2
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LINKS
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FORMULA
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a(n)=(1/3)[...[[[[n(2/1)](3/2)](4/3)](6/5)]...(k+1)/k]..., k>0 (mod 4), where [x] = floor of x; this infinite nested floor product will eventually level-off at a(n).
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EXAMPLE
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a(1)=1 since (1/4)[[[[1(2/1)](3/2)](4/3)](6/5)]=(1/4)[4(6/5)]=1
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CROSSREFS
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KEYWORD
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easy,nonn
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AUTHOR
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STATUS
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approved
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