A071866 Number of elements in the continued fraction for prime(n+1)/prime(n).

2, 3, 3, 4, 3, 3, 3, 4, 4, 3, 3, 3, 3, 4, 4, 4, 3, 3, 4, 3, 3, 4, 4, 3, 3, 3, 4, 3, 3, 3, 4, 4, 3, 4, 3, 3, 3, 4, 4, 4, 3, 3, 3, 3, 3, 6, 6, 4, 3, 3, 4, 3, 3, 4, 4, 4, 3, 3, 3, 3, 4, 4, 4, 3, 3, 6, 3, 5, 3, 3, 4, 4, 3, 3, 4, 4, 6, 3, 3, 4, 3, 3, 3, 3, 4, 4, 3, 3, 3, 4, 4, 4, 4, 5, 4, 4, 5, 3, 3, 3, 5, 4, 4, 3, 3

Offset

1,1

Links

Robert Israel, Table of n, a(n) for n = 1..10000

Example

prime(5)/prime(4) = 11/7, 11/7 continued fraction is [1, 1, 1, 3] which contains 4 elements, hence a(4)=4.

Maple

seq(nops(convert(ithprime(n+1)/ithprime(n), confrac)), n=1..200); # Robert Israel, May 29 2018

Mathematica

Table[Length[ContinuedFraction[Prime[n + 1]/Prime[n]]], {n, 105}] - Ray Chandler, Sep 18 2005

Prog

(PARI) for(n=1, 200, print1(length(contfrac(prime(n+1)/prime(n))), ", "))

Crossrefs

Cf. A110021, A109374, A112323, A112324, A112768.

Sequence in context: A215469 A007554 A139069 * A077603 A077567 A096344

Adjacent sequences: A071863 A071864 A071865 * A071867 A071868 A071869

Keyword

easy,nonn

Author

Benoit Cloitre, Jun 09 2002

Extensions

More terms from Hans Havermann, Jul 06 2002

Status

approved