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A060699 a(n) = floor(A^(C^n)), where A = 2.084551112207285611..., C = 1.221. 4
2, 2, 3, 5, 7, 11, 19, 37, 83, 223, 739, 3181, 18911, 166679, 2376391, 60953117, 3202432763, 403823050201 (list; graph; refs; listen; history; text; internal format)
OFFSET
1,1
COMMENTS
Results from the application of Caldwell's Generalized Mills's Theorem. This value of A produces 18 primes. For 20 primes A must be adjusted to 2.084551112207285611.
The extension of the sequence is guaranteed by the Cramer conjecture. That is: If the needed change in Y(n) for obtaining the next prime (superior or inferior) is as maximum = (log Y(n))^2/2, then the effect on Y(n-1) is less than K*C^(2n-1)*Y(n-1)/Y(n). K = (1/2)*(log A)^2 = 0.269784 This value diminishes with n. Example: For n = 23, a change in Y(23) by 2630 only changes Y(22) by 0.0043. _Jens Kruse Anderson_ with A = 2.084551112197624209091521123 calculated Y(n) = floor(A^(C^n)) from n = 1 to n = 3, obtaining 22 different primes. - Luis Rodriguez-Torres (ludovicusmagister(AT)yahoo.com), Feb 10 2009
REFERENCES
Jens Kruse Andersen. Personal communication (Feb 2009). [Luis Rodriguez-Torres (ludovicusmagister(AT)yahoo.com), Feb 10 2009]
O. Ore, Theory of Numbers and Its History. McGraw Hill, 1948.
LINKS
Carlos Rivera, Puzzle 85
FORMULA
a(n) = floor(A^(C^n)); A = 2.084551112... ; C = 1.221. - Luis Rodriguez-Torres (ludovicusmagister(AT)yahoo.com), Feb 10 2009
EXAMPLE
a(10) = 223 because 2.0845511122073^(1.221^10)= 223.58376...
With the value of A received from Jens K. Andersen we have: For n = 23, a(23) = 313 990 383 602 932 052 632 553 770 22009. - Luis Rodriguez-Torres (ludovicusmagister(AT)yahoo.com), Feb 10 2009
CROSSREFS
Sequence in context: A147997 A118987 A218557 * A284909 A062724 A126024
KEYWORD
nonn
AUTHOR
Luis Rodriguez-Torres (ludovicusmagister(AT)yahoo.com), Apr 20 2001
STATUS
approved

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Last modified May 20 16:51 EDT 2024. Contains 372719 sequences. (Running on oeis4.)