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A058282
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Continued fraction for e^3.
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4
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20, 11, 1, 2, 4, 3, 1, 5, 1, 2, 16, 1, 1, 16, 2, 13, 14, 4, 6, 2, 1, 1, 2, 2, 2, 3, 5, 1, 3, 1, 1, 68, 7, 5, 1, 4, 2, 1, 1, 1, 1, 1, 1, 7, 3, 1, 6, 1, 2, 5, 4, 7, 2, 1, 3, 2, 2, 1, 2, 1, 4, 1, 1, 13, 1, 1, 2, 1, 1, 1, 1, 3, 7, 11, 18, 54, 1, 2, 2, 2, 1, 1, 6, 2, 2, 46, 2, 189, 1, 24, 1, 8, 13, 4, 1, 1
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listen;
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OFFSET
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0,1
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LINKS
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K. Matthews, Finding the continued fraction of e^(l/m) ["... there is no known formula for the partial quotients of the continued fraction expansion of e^3, or more generally e^(l/m) with l distinct from 1,2 and gcd(l,m)=1..."]
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EXAMPLE
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20.085536923187667740928529... = 20 + 1/(11 + 1/(1 + 1/(2 + 1/(4 + ...)))). - Harry J. Smith, Apr 30 2009
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MAPLE
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with(numtheory); Digits:=200: cf:=convert(evalf( exp(3)), confrac); # N. J. A. Sloane, Sep 05 2012
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MATHEMATICA
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ContinuedFraction[ E^3, 100]
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PROG
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(PARI) contfrac(exp(1)^3)
(PARI) { allocatemem(932245000); default(realprecision, 21000); x=contfrac(exp(3)); for (n=1, 20001, write("b058282.txt", n-1, " ", x[n])); } \\ Harry J. Smith, Apr 30 2009
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CROSSREFS
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KEYWORD
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cofr,nonn,easy
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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