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A034300
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a(n) = n-th quintic factorial number divided by 3.
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13
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1, 8, 104, 1872, 43056, 1205568, 39783744, 1511782272, 65006637696, 3120318609408, 165376886298624, 9591859405320192, 604287142535172096, 41091525692391702528, 2999681375544594284544, 233975147292478354194432, 19419937225275703398137856, 1708954475824261899036131328
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OFFSET
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1,2
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LINKS
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FORMULA
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3*a(n) = (5*n-2)(!^5) = Product_{j=1..n} (5*j-2) = A047056(n).
E.g.f.: (1-5*x)^(-3/5)/3.
a(n) ~ sqrt(2*Pi) * 5/(3*Gamma(3/5)) * n^(11/10) * (5*n/e)^n * (1 + (169/300)/n - ...). - Joe Keane (jgk(AT)jgk.org), Nov 24 2001
D-finite with recurrence: a(n) +(-5*n+2)*a(n-1)=0. - R. J. Mathar, Feb 20 2020
Sum_{n>=1} 1/a(n) = 3*(e/5^2)^(1/5)*(Gamma(3/5) - Gamma(3/5, 1/5)). - Amiram Eldar, Dec 19 2022
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MAPLE
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a:= n-> mul(5*k-2, k=1..n)/3; seq(a(n), n=1..25); # G. C. Greubel, Aug 23 2019
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MATHEMATICA
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Table[Product[5j-2, {j, n}], {n, 20}]*1/3 (* Harvey P. Dale, Jul 25 2011 *)
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PROG
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(PARI) a(n) = prod(k=1, n, 5*k-2)/3;
(Magma) [(&*[5*k-2: k in [1..n]])/3: n in [1..25]]; // G. C. Greubel, Aug 23 2019
(Sage) [5^n*rising_factorial(3/5, n)/3 for n in (1..25)] # G. C. Greubel, Aug 23 2019
(GAP) List([1..25], n-> Product([1..n], k-> 5*k-2)/3 ); # G. C. Greubel, Aug 23 2019
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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